Poker odds question: What were the chances of me having A-2 and beating A-K twice is a row?

[RealEstate]

Basically the situation was I was heads up against my opponent, and I was short on time so I I went all in with 5k chips he called me with his 14k chips.





We flip them over and I have A-2 and he has A-k.



Flop misses everyone, so does the turn...then 2 on the river!



So then I am up to 10k and he has 9k.



VERY NEXT HAND. I get A-2 again...so I go all in again...he calls with A-K AGAIN!



Then the flop misses....turn misses..then a 2 again!



I win the sit and go and 47k fake chips.



So what were the chances of me I guess hitting a 3 outer twice in a row?



Or do I have to consider me getting a straight as well?



Thanks

[Murph550]

Assuming both of you were unsuited (Ace and Off not same suit) and you were holding opposite suits (one of you holding Club-Heart, other holding Spade-Diamond, to make the chances for a flush the same)...

Your chance to win the hand pre-flop is 23.82%., or about 1 in 4.2.

To hit it twice in a row, it's 1/4.2 times 1/4.2, or about 1/17.6 (about 5.6%).

So you have about a 5% chance to beat him twice in a row with those hands.

Now, this does not take into account the odds of actually having the exact 2 hands twice in a row.

The chance that you get A-2 again is 8/52 x 4/51, or 32/2652, or 1.2%.
The chance that he gets A-K is the same. 1.2%.
(not including suits)
So the chance that BOTH of you get the same hand twice in a row is 1.2% x 1.2%, or .01%. 1 in 10,000.

Combine that 1 in 10,000 shot with the 1 in 20 shot (5%) of beating him, and you have a 1 in 200,000 of the scenario you described playing out.

Note: This does include the chance that you hit a straight. Actually, he has the same chance to do so. It does NOT take into account that you hit the 2 on the river both times. It would make my brain explode trying to factor that in.

[packersown]

Very low